JEE toughest questions ever
The JEE (Joint Entrance Examination) is a route to enter in IITs. Basically, it is an engineering entrance examination conducted with a purpose to get admitted the qualified candidates. It is the most challenging exams where the number of students getsto participate every year.
The term ‘toughest’ is usually affixed by the students going to take this exam. The fact is that it is the toughest one because of having a massive list of a syllabus. Sometimes, even having a strong base, candidates become unable to crack it properly. The best advice for this is joining the JEE coaching will be the best as you will be able to understand basic and revision process is there as well.
If you are standing in the ending days of your JEE exam, let’s go through some tough questions that would be interrupted you on your exam day. Let’s understand this thoroughly so that you would crack it smartly:
For x∈R, f(x) = |log2 – sinx| and g(x) = f(f(x)), then:
(1) g is differentiable at x = 0 and g'(0) = –sin(log2)
(2) g is not differentiable at x = 0
(3) g'(0) = cos(log2)
(4) g'(0) = –cos(log2)
Ans. g'(0) = cos(log2)
If a curve y = f(x) passes through the point (1, –1) and fulfill the given differential equation, y(1 + xy) dx = x dy, then f(-1/2) is equal to:
(1) 4/5
(2) -2/5
(3) -4/5
(4) 2/5
Ans. 4/5
If the sum of the first ten terms of the series is (13/5) + (13/5) + (13/5) + 4 + (13/5) +…, is (16/5)m, then m is equal to:
(1) 99
(2) 102
(3) 101
(4) 100
Ans. 101
A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then:
(1) (4-π)x = πr
(2) x = 2r
(3) 2x = r
(4) 2x = (π + 4)r
Ans. 2r
The pair having the same magnetic moment is: [At. No.: Cr = 24, Mn = 25, Fe = 26, Co = 27]
(1) [Cr(H2O)6]2+ and [Fe(H2O)6]2+
(2) [Mn(H2O)6]2+ and [Cr(H2O)6]2+
(3) [CoCl4]2– and [Fe(H2O)6]2+
(4) [Cr(H2O)6]2+ and [CoCl4]2–
Ans. [Cr(H2O)6]2+ and [Fe(H2O)6]2+
The region between two concentric spheres of radii ‘a’ and ‘b’, respectively, has volume charge density ρ=A/r, where A is a constant and r is the distance from the centre. At the centre of the spheres is a point charge Q. The value of A such that the electric field in the region between the spheres will be constant, is:
(1) Q/[2π(b2-a2)]
(2) 2Q/[π(b2-a2)]
(3) 2Q/πa2
(4) Q/2πa2
Ans. Q/2πa2
Which one of the following complexes shows optical isomerism?
(1) cis[Co(en)2Cl2]Cl
(2) trans[Co(en)2Cl2]Cl
(3) [Co(NH3)4Cl2]Cl
(4) [Co(NH3)3Cl3] (en = ethylenediamine)
Ans. (cis[Co(en)2Cl2]Cl
A uniform string of length 20m is suspended from a rigid support. A short wave pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the support is: (take g = 10 ms–2)
(1) 2 s
(2) 2√2 s
(3) √2s
(4) 2π√2 s
Ans. 2√2 s
Decomposition of H2O2 follows a first order reaction. In fifty minutes the concentration of H2O2 decreases from 0.5 to 0.125 M in one such decomposition. When the concentration of H2O2 reaches 0.05 M, the rate of formation of O2 will be:
(1) 6.93×10-4 mol min-1
(2) 2.66 L min–1 at STP
(3) 1.34×10-2 mol min-1
(4) 6.93×10-2 mol min-1
Ans. 6.93×10-4 mol min-1
It’s time to prepare the JEE with a great enthusiasm. Never lose hope. May be you will be the part of the top list.
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